`y=lnroot(1/3)[(x-1)/(x+1)]`
`y=ln(x-1)^(1/3)-ln(x+1)^(1/3)`
`y=1/3ln(x-1)-1/3ln(x+1)`
`y'=1/[3(x-1)]-1/[3(x+1)]`
` ` `y'=[(x+1)-(x-1)]/[3(x-1)(x+1)]`
`y'=[x+1-x+1]/[3(x-1)(x+1)]`
`y'=2/[3(x-1)(x+1)]`
The derivative of function y is `2/[3(x-1)(x+1)]` .
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