Hello!
This differential equation is a separable one, it is possible to separate `y` from `x.` For this, simply divide both sides by `(y^2+4):`
`(y')/(y^2+4) = 1/(x^2+16).`
`y` is at the left side only, `x` is at the right side only. Moreover, both sides are integrable in elementary functions:
`1/2 arctan(y/2) = 1/4 arctan(x/4)+C,`
or `arctan(y/2) = 1/2 arctan(x/4)+C.` (1)
Now use the given boundary condition, `y(4)=1,` to find `C:`
`arctan(1/2) = 1/2 arctan(1) + C,` or
`C =arctan(1/2) - 1/2 arctan(1) = arctan(1/2) - pi/8.`
If we take `tan` of the both sides of (1), we obtain
`y(x)=2tan(1/2 arctan(x/4)+arctan(1/2)-pi/8).`
This is the only solution.
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