For the stated word problem, we need to use variable to represent the unknown counts per each fruit. We may let:
o = original number of oranges
a= original number of apples
p = original number of pears.
To set-up an equation, we translate the given conditions in the problem.
Condition 1: A fruiterer had the same number of apples, pears and oranges at first.
This implies that we can equate them as .
Condition 2:After 98 oranges, some apples and pears were sold, there were 392 fruits left.
We may let:
unsold oranges = o'
unsold apples = a'
unsold pears = p'
It indicates that the sum of the remaining number of fruits = 392 such that: sold oranges =98
Condition 3: There were thrice as many apples as pears left
This means that or
Condition 4: The number of oranges left was 35 fewer than the number of apples left.
Using , we get:
Applying condition 3: and condition 4:
on condition 2:
p'=61 as the number of "unsold pears".
Plug-in on
, we get:
as number of unsold oranges
With sold oranges = 98 and unsold oranges=148 then
original number of oranges: .
Applying , we can determine that we also have:
246 original number of pears and 61 unsold pears.
Then,
sold pears: [FINAL ANSWER]
In addition, the other unsold apples and oranges are:
Plug-in on
, we get:
as number of unsold apples
then sold apples:
Here is the tally.
Number of sold fruits: 63 apples, 185 pears, and 98 oranges
Number of unsold fruits: 183 apples, 61 pears, and 148 oranges
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