We know how much energy we need altogether: 14 kilowatts. So all we need to do is figure out the energy of each transition, and then that will tell us how many transitions we need.
The energy of the photon emitted by the transition is given by its wavelength according to this equation:
`E = {h c}/lambda `
Plug that in, and we have:
`E = (6.626 * 10^-34 J * s)(3.00 * 10^8 m/s)/(1.270 *10^-9 m) = 1.565*10^-16 J`
So now, we just divide that into 14 kW:
`(1.4*10^4 W)/(1.565*10^-16 J) = 8.946*10^19 s^{-1}`
So we need `8.946*10^19` atomic transitions per second.
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