Wednesday, August 4, 2010

general solution cos (4x-60)=sin2x [-90:90]

Solve `cos(4x-60^@)=sin2x ` :


`cos(4x-60^@)=sin2x `


`sin(4x+30^@)=sin2x `


Take the inverse sine of both sides:


1. `4x+30=180-2x+360n ` where n is an integer.


6x=150+360n


x=25+60n


or


2. 4x+30=2x+360n


2x=-30+360n


x=-15+180n


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The general solution is x=25+60n for n an integer or x=-15+180n for n an integer.


On the interval [-90,90] the solutions are x=-35,-15,25,85


Here is the graph: the left side in black and the right side in red:



convert the scale from radian to degrees.

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